我有这样一本字典，
data = {'04-01-2012': [{1: 0.93}, {2: 0.9195000000000001}, {3: 0.9090000000000001}, {4: 0.8985000000000002},
{5: 0.8880000000000002}, {6: 0.8775000000000003}, {7: 0.8670000000000003},
{8: 0.8565000000000004}, {9: 0.8460000000000004}],
'12-01-2012': [{1: 0.96}],
'07-01-2012': [{1: 0.96}, {2: 0.95}, {3: 0.94}, {4: 0.9299999999999999}, {5: 0.9199999999999999},
{6: 0.9099999999999999}],
'06-01-2012': [{1: 0.945}, {2: 0.9365}, {3: 0.928}, {4: 0.9195000000000001}, {5: 0.9110000000000001},
{6: 0.9025000000000002}, {7: 0.8940000000000002}],
'10-01-2012': [{1: 0.93}, {2: 0.9244}, {3: 0.9188}],
'05-01-2012': [{1: 0.935}, {2: 0.926}, {3: 0.917}, {4: 0.908}, {5: 0.899}, {6: 0.89}, {7: 0.881}, {8: 0.872}],
'11-01-2012': [{1: 0.945}, {2: 0.9325}],
'02-01-2012': [{1: 0.94}, {2: 0.9299999999999999}, {3: 0.9199999999999999}, {4: 0.9099999999999999},
{5: 0.8999999999999999}, {6: 0.8899999999999999}, {7: 0.8799999999999999},
{8: 0.8699999999999999}, {9: 0.8599999999999999}, {10: 0.8499999999999999},
{11: 0.8399999999999999}],
'03-01-2012': [{1: 0.955}, {2: 0.9455}, {3: 0.936}, {4: 0.9265000000000001}, {5: 0.9170000000000001},
{6: 0.9075000000000002}, {7: 0.8980000000000002}, {8: 0.8885000000000003},
{9: 0.8790000000000003}, {10: 0.8695000000000004}],
'08-01-2012': [{1: 0.94}, {2: 0.9295}, {3: 0.919}, {4: 0.9085000000000001}, {5: 0.8980000000000001}],
'01-01-2012': [{1: 0.95}, {2: 0.94}, {3: 0.9299999999999999}, {4: 0.9199999999999999}, {5: 0.9099999999999999},
{6: 0.8999999999999999}, {7: 0.8899999999999999}, {8: 0.8799999999999999},
{9: 0.8699999999999999}, {10: 0.8599999999999999}, {11: 0.8499999999999999},
{12: 0.8399999999999999}],
'09-01-2012': [{1: 0.92}, {2: 0.91}, {3: 0.9}, {4: 0.89}]}
我需要遍历字典值并将所有 1、2 等分组。
到目前为止，这是我的代码
from collections import defaultdict
final = defaultdict(list)
for k, v in data.items():
new_data = next(iter(v))
for m, n in new_data.items():
final[m].append(n)
print(final)
# defaultdict(<class 'list'>, {1: [0.935, 0.92, 0.955, 0.96, 0.94, 0.93, 0.95, 0.96, 0.945, 0.94, 0.945, 0.93]})
它只对所有 1 进行分组，不对 2 进行分组，依此类推。我做错了什么？
请您参考如下方法:
你忘了遍历许多小字典:
from collections import defaultdict
final = defaultdict(list)
for k, v in data.items():
for d in v: # <-- this was missing
for m, n in d.items():
final[m].append(n)
print(final)
(您只调用了 next(...)，它只产生第一个项目。)
输出:
defaultdict(, {1: [0.96, 0.935, 0.93, 0.945, 0.96, 0.95, 0.93, 0.94, 0.945, 0.955, 0.94, 0.92], 2: [0.926, 0.9244, 0.9365, 0.95, 0.94, 0.9195000000000001, 0.9299999999999999, 0.9325, 0.9455, 0.9295, 0.91], 3: [0.917, 0.9188, 0.928, 0.94, 0.9299999999999999, 0.9090000000000001, 0.9199999999999999, 0.936, 0.919, 0.9], 4: [0.908, 0.9195000000000001, 0.9299999999999999, 0.9199999999999999, 0.8985000000000002, 0.9099999999999999, 0.9265000000000001, 0.9085000000000001, 0.89], 5: [0.899, 0.9110000000000001, 0.9199999999999999, 0.9099999999999999, 0.8880000000000002, 0.8999999999999999, 0.9170000000000001, 0.8980000000000001], 6: [0.89, 0.9025000000000002, 0.9099999999999999, 0.8999999999999999, 0.8775000000000003, 0.8899999999999999, 0.9075000000000002], 7: [0.881, 0.8940000000000002, 0.8899999999999999, 0.8670000000000003, 0.8799999999999999, 0.8980000000000002], 8: [0.872, 0.8799999999999999, 0.8565000000000004, 0.8699999999999999, 0.8885000000000003], 9: [0.8699999999999999, 0.8460000000000004, 0.8599999999999999, 0.8790000000000003], 10: [0.8599999999999999, 0.8499999999999999, 0.8695000000000004], 11: [0.8499999999999999, 0.8399999999999999], 12: [0.8399999999999999]})
