我一直在研究这个程序，任何形式的帮助都将不胜感激。
查找两年之间的闰年并将其添加到数组中的程序...

from array import array 
 
x=int(input("Enter the year ")) 
print("the year you entered is",x) 
 
while x<=2017: 
    if x%4==0: 
        print(x) 
        n=array('i',[x]) 
        n.append(x) 
        x=x+1 
    else: 
        x=x+1 
print(n) 

输出

enter the year 1992 
the year you entered is 1992 
1992 
1996 
2000 
2004 
2008 
2012 
2016 
array('i', [2016, 2016]) 

请您参考如下方法:

问题是每当一年被 4 整除时，您都会重新设置数组的值。您要做的是在循环外声明数组。

from array import array 
 
x=int(input("enter the year from which you want to know the leap year from")) 
print("the year you entered is",x) 
 
n=array('i') 
while x<=2017: 
    if (x % 4 == 0 and x % 100 != 0) or x % 400 == 0: 
        print(x)    
        n.append(x) 
    x += 1  # we need to add 1 regardless, no need for else   
print(n) 
# output: array('i', [1992, 1996, 2000, 2004, 2008, 2012, 2016])