python之如何返回 Django 中两个团队的所有组合

我正在研究锦标赛管理器，并且开始研究比赛系统。我的问题是如何返回两支球队的所有组合，然后我才能用这些组合创建比赛？
让我解释一下。一个团队只属于一个池。在“团队”模型中， 我有一个引用团队所属池的外键字段。在我的算法中，我想创建由属于同一池的两支球队进行的比赛。例如我有 A、B、C、D 队，我想创建比赛 A 对 B，比赛 A 对 C，比赛 A 对 D，等等

我在这里看了一点:https://docs.python.org/3/library/itertools.html ，我找到了“组合”功能，但仅此而已。

models.py

class Match(models.Model): 
    scoreTeam1  = models.IntegerField() 
    scoreTeam2  = models.IntegerField() 
    phase       = models.ForeignKey(Phase, default=None, on_delete=models.CASCADE) 
    teams       = models.ManyToManyField(Team, default=None, blank=True) 
 
class Pool(models.Model): 
    name    = models.CharField(max_length=16) 
    nbTeam  = models.IntegerField(validators=[ 
                                    MaxValueValidator(4), 
                                    MinValueValidator(3) 
                                ]) 
    phase   = models.ForeignKey(Phase, default=None, on_delete=models.CASCADE) 
    field   = models.ForeignKey(Field, default=None, on_delete=models.CASCADE) 
 
class Team(models.Model): 
    name        = models.CharField(max_length=16) 
    totalpoints = models.IntegerField(default=0) 
    position    = models.IntegerField(default=0) 
    category    = models.ForeignKey(Category, default=None, on_delete=models.CASCADE) 
    pool        = models.ForeignKey(Pool, default=None, blank=True, null=True, on_delete=models.SET_NULL) 

views.py

def matches_phase_view(request, id, id_phase, *args, **kwargs): 
    tournaments = Tournament.objects.filter(user=request.user) 
    tournament = Tournament.objects.get(pk=id) 
    phase = Phase.objects.get(pk=id_phase) 
    pools = Pool.objects.filter(phase=phase) 
    teams = Team.objects.filter(pool__in=pools) 
 
    matches_count = 0 
    for pool in pools: 
        matches_count = matches_count + pool.nbTeam * (pool.nbTeam - 1) // 2 
    for pool in pools: 
        teams_combinations = combinations(Team.objects.filter(pool=pool), 2) 
        list_teams_combinations = list(teams_combinations) 
        for combination in list_teams_combinations: 
            match = Match.objects.create(phase=phase) 
            match.teams.add(combination[0]) 
            match.teams.add(combination[1]) 
            match.save() 
 
    matches = Match.objects.filter(phase=phase) 
    context = { 
        'tournaments': tournaments, 
        'tournament': tournament, 
        'pools': pools, 
        'teams': teams, 
        'matches_count': matches_count, 
        'matches': matches, 
    } 
    return render(request, 'tournament_manage_phase_matches.html', context) 

我试过这个:

for pool in pools: 
        a = combinations(Team.objects.filter(pool=pool), 2) 

但是我遇到了这个错误:

name 'combinations' is not defined

如果有人有更好的主意，我想听听。

我正在使用 Python 3.7、Django 2.2。

编辑:

模板

{% extends 'base_tournament.html' %} 
 
{% load crispy_forms_tags %} 
 
{% block title %} 
  Tournament 
{% endblock %} 
 
{% block navbar_manage %} 
    {% include 'navbar_manage.html' %} 
{% endblock %} 
 
{% block content %} 
    <h1>Matches of ...</h1> 
 
    <ul class="nav nav-tabs" id="myTab" role="tablist"> 
    {% for pool in pools %} 
        <li class="nav-item"> 
            <a class="nav-link" id="{{ pool.name }}-tab" data-toggle="tab" href="#{{ pool.name }}" role="tab" aria-controls="{{ pool.name }}" aria-selected="true">{{ pool.name }}</a> 
        </li> 
    {% endfor %} 
    </ul> 
    <div class="tab-content" id="myTabContent"> 
        {% for pool in pools %} 
            <div class="tab-pane fade" id="{{ pool.name }}" role="tabpanel" aria-labelledby="{{ pool.name }}-tab"> 
                {% for match in matches %} 
                    <p>Wait for a moment</p> 
                {% endfor %} 
            </div> 
        {% endfor %} 
    </div> 
 
{% endblock %} 

请您参考如下方法:

从 itertools 导入组合