我正在尝试使用 google oauth 和 gmail api 服务从我的 gmail 帐户解析每个邮件正文。目前我只能获取消息 ID 和线程 ID，当我打开它们时根本没有任何意义。 所以我使用的以下代码如下:
from __future__ import print_function
import pickle
import os.path
from googleapiclient.discovery import build
from google_auth_oauthlib.flow import InstalledAppFlow
from google.auth.transport.requests import Request
# If modifying these scopes, delete the file token.pickle.
SCOPES = ['https://www.googleapis.com/auth/gmail.readonly']
def main():
"""Shows basic usage of the Gmail API.
Lists the user's Gmail labels.
"""
creds = None
# The file token.pickle stores the user's access and refresh tokens, and is
# created automatically when the authorization flow completes for the first
# time.
if os.path.exists('token.pickle'):
with open('token.pickle', 'rb') as token:
creds = pickle.load(token)
# If there are no (valid) credentials available, let the user log in.
if not creds or not creds.valid:
if creds and creds.expired and creds.refresh_token:
creds.refresh(Request())
else:
flow = InstalledAppFlow.from_client_secrets_file(
'credentials.json', SCOPES)
creds = flow.run_local_server()
# Save the credentials for the next run
with open('token.pickle', 'wb') as token:
pickle.dump(creds, token)
service = build('gmail', 'v1', credentials=creds)
# Call the Gmail API
results = service.users().labels().list(userId='me').execute()
print(service.users().messages().list(userId='me').execute())
print(service.users().messages().get(userId='me', id='16931216e3a05048').execute())
labels = results.get('labels', [])
if not labels:
print('No labels found.')
else:
print('Labels:')
for label in labels:
print(label['name'])
if __name__ == '__main__':
main()
对于使用此行 print(service.users().messages().get(userId='me', id='16931216e3a05048') 的消息 ID 之一，我得到的输出是这样的。执行())
请您参考如下方法:
你忘记添加格式了
message = service.users().messages().get(userId=user_id, id=msg_id,
format='raw').execute()
print 'Message snippet: %s' % message['snippet']
msg_str = base64.urlsafe_b64decode(message['raw'].encode('ASCII'))
mime_msg = email.message_from_string(msg_str)
