python之使用正则表达式获取两个字符之间的值(Python 3)

import re 
 
value = "world_wide='test1/one/two', " \ 
        "stage_test='ALPHA', world_wide='test2/one/two', " \ 
        "stage_test='GAMMA', world_wide='test3/one/two', " \ 
        "stage_test='GAMMA', world_wide='test4/one/two', " \ 
        "stage_test='ALPHA', world_wide='test5/one/two', " \ 
        "stage_test='GAMMA', world_wide='test6/one/two', " \ 
        "stage_test='GAMMA" 
 
pattern = r"(world_wide=\'.*\')" 
 
for match in re.findall(pattern, str(value)): 
    print ("\n", match) 

尝试过滤给定字符串值的特定输出。上面的代码给出了以下输出:

 world_wide='test1/one/two', stage_test='ALPHA', world_wide='test2/one/two', stage_test='GAMMA', world_wide='test3/one/two', stage_test='GAMMA', world_wide='test4/one/two', stage_test='ALPHA', world_wide='test5/one/two', stage_test='GAMMA', world_wide='test6/one/two', stage_test=' 

我想要得到的是:如果字符串匹配特定条件，例如:

如果找到 'world_wide='，则返回两个字符之间的以下值。在这种情况下，这将是两个单引号，不包括 '/one/two'。

期望的输出:

>>>test1 
test2 
test3 
test4 
......... 

请您参考如下方法:

您可以使用以下表达式:

world_wide='([^/]+) 
# world_wide=' 
# capture anything not a / into group 1 

---

在 Python 中是:

import re 
 
value = "world_wide='test1/one/two', " \ 
        "stage_test='ALPHA', world_wide='test2/one/two', " \ 
        "stage_test='GAMMA', world_wide='test3/one/two', " \ 
        "stage_test='GAMMA', world_wide='test4/one/two', " \ 
        "stage_test='ALPHA', world_wide='test5/one/two', " \ 
        "stage_test='GAMMA', world_wide='test6/one/two', " \ 
        "stage_test='GAMMA" 
 
rx = re.compile(r'''world_wide='([^/]+)''') 
parts = rx.findall(value) 
print(parts) 

这会产生一个包含

的列表

['test1', 'test2', 'test3', 'test4', 'test5', 'test6'] 

参见 a demo on regex101.com .