python之使用选项创建自定义 Django CharField

我在 models.py 文件中有以下代码:

SENT = 0 
ACEPTED = 1 
DECLINED = 2 
 
SHARE_STATUSES = ( 
  (SENT, 'Sent'), 
  (ACCEPTED, 'Approved'), 
  (DECLINED, 'Declined') 
) 
 
status = models.ResultStatusField(max_length=2, choices=STATUS_CHOICES, default=SENT) 

我想创建一个带有选项的自定义 Django 字段类型(可以在整个应用程序模块中重复使用，而不是在不同的地方多次复制粘贴)。

我读过 Django reference关于如何创建自定义字段，但不了解如何提供选择。

class ResultStatusField(models.CharField): 
  def __init__(self): 
    SENT = 0 
    ACCEPTED = 1 
    DECLINED = 2 
 
    SHARE_STATUSES = ( 
      (SENT, 'Sent'), 
      (ACCEPTED, 'Approved'), 
      (DECLINED, 'Declined') 
    ) 

感谢您的帮助。

请您参考如下方法:

只需将 choices 添加到关键字参数:

class ResultStatusField(models.CharField): 
 
  def __init__(self, *args, **kwargs): 
 
    SENT = 0 
    ACCEPTED = 1 
    DECLINED = 2 
 
    SHARE_STATUSES = ( 
      (SENT, 'Sent'), 
      (ACCEPTED, 'Approved'), 
      (DECLINED, 'Declined') 
    ) 
 
    kwargs['choices'] = SHARE_STATUSES 
    kwargs['default'] = SENT 
    kwargs['max_length'] = 2 
 
    super(ResultStatusField, self).__init__(*args, **kwargs)