c#之在 WP7 上显示来自 Web 服务的 JSON 数据

我正在尝试在我的应用程序中解析和显示使用网络客户端检索到的 JSON 数据。这里是我要显示的json字符串

{"metadata":{"page":1,"perPage":23,"count":23},"results":[{"id":9,"name":"Breaks","slug":"breaks","subgenres":[]},{"id":10,"name":"Chill Out","slug":"chill-out","subgenres":[]},{"id":12,"name":"Deep House","slug":"deep-house","subgenres":[]},{"id":16,"name":"DJ Tools","slug":"dj-tools","subgenres":[]},{"id":1,"name":"Drum & Bass","slug":"drum-and-bass","subgenres":[]},{"id":18,"name":"Dubstep","slug":"dubstep","subgenres":[]},{"id":17,"name":"Electro House","slug":"electro-house","subgenres":[]},{"id":3,"name":"Electronica","slug":"electronica","subgenres":[]},{"id":40,"name":"Funk \/ R&B","slug":"funk-r-and-b","subgenres":[]},{"id":49,"name":"Glitch Hop","slug":"glitch-hop","subgenres":[]},{"id":8,"name":"Hard Dance","slug":"hard-dance","subgenres":[]},{"id":2,"name":"Hardcore \/ Hard Techno","slug":"hardcore-hard-techno","subgenres":[]},{"id":38,"name":"Hip-Hop","slug":"hip-hop","subgenres":[]},{"id":5,"name":"House","slug":"house","subgenres":[]},{"id":37,"name":"Indie Dance \/ Nu Disco","slug":"indie-dance-nu-disco","subgenres":[]},{"id":14,"name":"Minimal","slug":"minimal","subgenres":[]},{"id":39,"name":"Pop \/ Rock","slug":"pop-rock","subgenres":[]},{"id":15,"name":"Progressive House","slug":"progressive-house","subgenres":[]},{"id":13,"name":"Psy-Trance","slug":"psy-trance","subgenres":[]},{"id":41,"name":"Reggae \/ Dub","slug":"reggae-dub","subgenres":[]},{"id":11,"name":"Tech House","slug":"tech-house","subgenres":[]},{"id":6,"name":"Techno","slug":"techno","subgenres":[]},{"id":7,"name":"Trance","slug":"trance","subgenres":[]}]} 

更新

当它进入 foreach 循环时，我现在得到一个 NullReferenceException。由于某种原因，它无法识别“数据”

    // Deserialize the Data 
    void beatportTest_GetDataCompleted(object sender, OpenReadCompletedEventArgs e) 
    { 
        DataContractJsonSerializer serializer = null; 
 
        try 
        { 
            serializer = new DataContractJsonSerializer(typeof(ObservableCollection<Result>)); 
            ObservableCollection<Result> data = serializer.ReadObject(e.Result) as ObservableCollection<Result>; 
 
            // foreach loop to display data 
            foreach (Result genre in data) 
            { 
                string name = genre.name; 
                listGenres.Items.Add(name); 
            } 
        } 
        catch (Exception ex) 
        { 
            MessageBox.Show(ex.Message); 
        } 
    } 

这是我的类(class)。

    public class Genres 
    { 
        public Metadata metadata { get; set; } 
        public List<Result> results { get; set; } 
    } 
 
    public class Metadata 
    { 
        public int page { get; set; } 
        public int perPage { get; set; } 
        public int count { get; set; } 
    } 
 
    public class Result 
    { 
        public int id { get; set; } 
        public string name { get; set; } 
        public string slug { get; set; } 
        // public List<object> subgenres { get; set; } 
    } 

离开 L.B 的更新类(class)“我需要做什么才能使用“名称”字段显示所有类型的文本 block ？下面是我的 xaml。

        <controls:PanoramaItem x:Name="genres" Header="genres"> 
            <!--Single line list--> 
            <Grid 
                <ListBox x:Name="listGenres" Margin="0,95,0,0"> 
                    <ListBox.ItemTemplate> 
                        <DataTemplate> 
                            <StackPanel Width="432" Height="78"> 
                                <TextBlock Text="???"  Style="{StaticResource PhoneTextExtraLargeStyle}" />                                       
                            </StackPanel> 
                        </DataTemplate> 
                    </ListBox.ItemTemplate> 
                </ListBox>        
            </Grid>         
        </controls:PanoramaItem> 

再次感谢。

请您参考如下方法:

这是我用来反序列化你的 json 字符串的类定义

public class Genres 
{ 
    public Metadata metadata; 
    public Result[] results; 
} 
 
public class Metadata 
{ 
    public int page; 
    public int perPage; 
    public int count; 
} 
 
public class Result 
{ 
    public int id; 
    public string name; 
    public string slug; 
    //public subgenre[] subgenres; 
} 
 
 
DataContractJsonSerializer serializer = new DataContractJsonSerializer(typeof(Genres)); 
Genres data = serializer.ReadObject(e.Result) as Genres;