Skip to main content
 首页 » 编程设计

Python 正则表达式,条件搜索

2024年08月26日29lyhabc

我正在尝试拆分这句话

"Mr. Smith bought cheapsite.com for 1.5 million dollars, i.e. he paid a lot " \ 
"for it. Did he mind? Adam Jones Jr. thinks he didn't. In any case, this " \ 
"isn't true... Well, with a probability of .9 it isn't." 

进入下面的列表。

Mr. Smith bought cheapsite.com for 1.5 million dollars, i.e. he paid a lot for it. 
Did he mind? 
Adam Jones Jr. thinks he didn't. 
In any case, this isn't true... 
Well, with a probability of .9 it isn't. 

代码:

print re.findall('([A-Z]+[^.].*?[a-z.][.?!] )[^a-z]',text) 

输出:

['Mr. Smith bought cheapsite.com for 1.5 million dollars, i.e. he paid 
 a lot for it. ', "Adam Jones Jr. thinks he didn't. "] 

K gud,但它遗漏了一些,有没有办法告诉 Python,因为最后一个 [^a-z] 不属于我的组,请从那里继续搜索。

编辑:

这是通过@sputnick 提到的前瞻性正则表达式实现的。

print re.findall('([A-Z]+[^.].*?[a-z.][.?!] )(?=[^a-z])',text) 

输出:

['Mr. Smith bought cheapsite.com for 1.5 million dollars, i.e. he paid 
 a lot for it. ', 'Did he mind? ', "Adam Jones Jr. thinks he didn't. " 
, "In any case, this isn't true... "] 

但是我们还需要最后一句。有什么想法吗?

请您参考如下方法:

试试这个:

print re.findall('([A-Z]+[^.].*?[a-z.][.?!] )(?=[^a-z])',text) 

使用正向预测正则表达式技术,检查http://www.regular-expressions.info/lookaround.html