我的时间很紧，想出一个 python 正则表达式来匹配许多可能的不同版权声明中的公司名称，例如:
Copyright © 2019 Apple Inc. All rights reserved.
© 2019 Quid, Inc. All Rights Reserved.
© 2009 Database Designs
© 2019 Rediker Software, All Rights Reserved
©2019 EVOSUS, INC. ALL RIGHTS RESERVED
© 2019 Walmart. All Rights Reserved.
© Copyright 2003-2019 Exxon Mobil Corporation. All Rights Reserved.
Copyright © 1978-2019 Berkshire Hathaway Inc.
© 2019 McKesson Corporation
© 2019 UnitedHealth Group. All rights reserved.
© Copyright 1999 - 2019 CVS Health
Copyright 2019 General Motors. All Rights Reserved.
© 2019 Ford Motor Company
©2019 AT&T Intellectual Property. All rights reserved.
© 2019 GENERAL ELECTRIC
Copyright ©2019 AmerisourceBergen Corporation. All Rights Reserved.
© 2019 Verizon
© 2019 Fannie Mae
Copyright © 2018 Jonas Construction Software Inc. All rights reserved.
All Comments © Copyright 2017 Kroger | The Kroger Co. All Rights Reserved
© 2019 Express Scripts Holding Company. All Rights Reserved. 1 Express Way, St. Louis, MO 63121
© 2019 JPMorgan Chase & Co.
Copyright © 1995 - 2018 Boeing. All Rights Reserved.
© 2019 Bank of America Corporation. All rights reserved.
© 1999 - 2019 Wells Fargo. All rights reserved. NMLSR ID 399801
©2019 Cardinal Health. All rights reserved.
我对正则表达式的了解只是非常基本的东西，目前还不足以快速想出一个好的解决方案。
在我看来，至少对于这些示例，正确捕获公司名称的要求如下:
If there's a '©' or 'Copyright' in the sentence:
After '©' or 'Copyright' - look for a year, e.g. '2019', or a year range, e.g. '1995 - 2018' or '2003-2019' (spaces are to catch as well]):
If there's a dot somewhere after this year/year range, capture the text until the dot. E.g. in 'Copyright © 1978-2019 Berkshire Hathaway Inc.' capture 'Berkshire Hathaway Inc'
If there's no dot but there's the sentence 'All rights reserved', capture from the year/year range until there and also ignore any possible non-alphanumeric characters that precede it, such as spaces and commas. E.g. from '© 2019 Rediker Software, All Rights Reserved' capture 'Rediker Software'
If there's no dot nor the sentence 'All rights reserved', capture from the year/year range until the end. E.g. from '© 2019 Verizon' Capture 'Verizon'
有什么关于好的正则表达式的建议吗？
请您参考如下方法:
你可以考虑像这样的正则表达式
(?i)(?:©(?:\s*Copyright)?|Copyright(?:\s*©)?)\s*\d+(?:\s*-\s*\d+)?\s*(.*?(?=\W*All\s+rights\s+reserved)|[^.]*(?=\.)|.*)
参见 regex demo .使用不区分大小写的修饰符，re.I与它。
详情
-
(?:©(?:\s*Copyright)?|Copyright(?:\s*©)?)- 任何一个-
©(?:\s*Copyright)?-©char 后跟一个可选的 0+ 空格子字符串，然后是Copyright -
|- 或者 -
Copyright(?:\s*©)?-Copyright后跟可选的 0+ 空格子串和©字符
-
-
\s*- 0+ 个空格 -
\d+- 1+ 位数字(如果年份始终包含 4 位数字，则使用\d{4}) -
(?:\s*-\s*\d+)?--的可选序列用 0+ 个空格和 1+ 个数字括起来(如果年份始终包含 4 位数字，请使用\d{4}) -
\s*- 0+ 个空格 -
(.*?(?=\W*All\s+rights\s+reserved)|[^.]*(?=\.)|.*)- 捕获第 1 组:任何备选方案:-
.*?(?=\W*All\s+rights\s+reserved)- 除换行符以外的任何 0+ 个字符，尽可能少，直到 0+ 个非单词字符后跟All rights reserved字符串 -
[^.]*(?=\.)- 除.以外的任何 0+ 个字符尽可能多到.不包括. -
.*- 其余部分
-
import re
s = "Copyright © 2019 Apple Inc. All rights reserved.\r\n© 2019 Quid, Inc. All Rights Reserved.\r\n© 2009 Database Designs \r\n© 2019 Rediker Software, All Rights Reserved\r\n©2019 EVOSUS, INC. ALL RIGHTS RESERVED\r\n© 2019 Walmart. All Rights Reserved.\r\n© Copyright 2003-2019 Exxon Mobil Corporation. All Rights Reserved.\r\nCopyright © 1978-2019 Berkshire Hathaway Inc.\r\n© 2019 McKesson Corporation\r\n© 2019 UnitedHealth Group. All rights reserved.\r\n© Copyright 1999 - 2019 CVS Health\r\nCopyright 2019 General Motors. All Rights Reserved.\r\n© 2019 Ford Motor Company\r\n©2019 AT&T Intellectual Property. All rights reserved.\r\n© 2019 GENERAL ELECTRIC\r\nCopyright ©2019 AmerisourceBergen Corporation. All Rights Reserved.\r\n© 2019 Verizon\r\n© 2019 Fannie Mae\r\nCopyright © 2018 Jonas Construction Software Inc. All rights reserved.\r\nAll Comments © Copyright 2017 Kroger | The Kroger Co. All Rights Reserved\r\n© 2019 Express Scripts Holding Company. All Rights Reserved. 1 Express Way, St. Louis, MO 63121\r\n© 2019 JPMorgan Chase & Co.\r\nCopyright © 1995 - 2018 Boeing. All Rights Reserved.\r\n© 2019 Bank of America Corporation. All rights reserved.\r\n© 1999 - 2019 Wells Fargo. All rights reserved. NMLSR ID 399801\r\n©2019 Cardinal Health. All rights reserved.\r\n© 2019 Quid, Inc All Rights Reserved."
rx = r"(?:©(?:\s*Copyright)?|Copyright(?:\s*©)?)\s*\d+(?:\s*-\s*\d+)?\s*(.*?(?=\W*All\s+rights\s+reserved)|[^.\n]*(?=\.)|.*)"
for m in re.findall(rx, s, re.I):
print(m)
输出:
Apple Inc
Quid, Inc
Database Designs
Rediker Software
EVOSUS, INC
Walmart
Exxon Mobil Corporation
Berkshire Hathaway Inc
McKesson Corporation
UnitedHealth Group
CVS Health
General Motors
Ford Motor Company
AT&T Intellectual Property
GENERAL ELECTRIC
AmerisourceBergen Corporation
Verizon
Fannie Mae
Jonas Construction Software Inc
Kroger | The Kroger Co
Express Scripts Holding Company
JPMorgan Chase & Co
Boeing
Bank of America Corporation
Wells Fargo
Cardinal Health
Quid, Inc
