我需要从一个字符串中匹配一个模式。字符串是可变的,所以我需要在其中开发一些可变性。
我需要做的是提取与“布局”一起出现的单词,它们以 4 种不同的方式出现
1 word -- layout` eg: hsr layout
2words -- layout eg: golden garden layout
digit-word -- layout eg: 19th layout
digit-word word --layout eg:- 20th garden layout
可以看出,我需要数字字段是可选的。一个正则表达式必须做到这一点。这是我所做的:
import re
p = re.compile(r'(?:\d*)?\w+\s(?:\d*)?\w+l[ayout]*')
text = "opp when the 19th hsr layut towards"
q = re.findall(p,text)
在这个表达式中我需要 19th hsr 布局。但是上面的代码没有返回。我上面的代码有什么问题?
一些字符串示例是:
str1 = " 25/4 16th june road ,watertank layout ,blr" #extract watertank layout
str2 = " jacob circle 16th rusthumbagh layout , 5th cross" #extract 16th rustumbagh layout
str3 = " oberoi splendor garden blossoms layout , 5th main road" #extract garden blossoms layout
str4 = " belvedia heights , 15th layout near Jaffrey gym" #extract 15th layout
请您参考如下方法:
按照我的评论使用 r'(?:\w+\s+){1,2}layout':
>>> import re
>>> p = re.compile(r'(?:\w+\s+){1,2}layout')
>>> p.findall(" 25/4 16th june road ,watertank layout ,blr")
['watertank layout']
>>> p.findall(" jacob circle 16th rusthumbagh layout , 5th cross")
['16th rusthumbagh layout']
>>> p.findall(" oberoi splendor garden blossoms layout , 5th main road")
['garden blossoms layout']
>>> p.findall(" belvedia heights , 15th layout near Jaffrey gym")
['15th layout']
{1,2} 用于匹配最多 2 个单词。
