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python之Tensorflow:如何使用 dynamic_rnn 从 LSTMCell 获取中间单元状态 (c)

2024年10月01日29kevingrace

默认情况下,函数 dynamic_rnn 只输出每个时间点的隐藏状态(称为 m),可以通过以下方式获得:

cell = tf.contrib.rnn.LSTMCell(100) 
rnn_outputs, _ = tf.nn.dynamic_rnn(cell, 
                                   inputs=inputs, 
                                   sequence_length=sequence_lengths, 
                                   dtype=tf.float32) 

有没有办法另外获得中间(非最终)细胞状态(c)?

tensorflow 贡献者 mentions它可以用细胞包装来完成:

class Wrapper(tf.nn.rnn_cell.RNNCell): 
  def __init__(self, inner_cell): 
     super(Wrapper, self).__init__() 
     self._inner_cell = inner_cell 
  @property 
  def state_size(self): 
     return self._inner_cell.state_size 
  @property 
  def output_size(self): 
    return (self._inner_cell.state_size, self._inner_cell.output_size) 
  def call(self, input, state) 
    output, next_state = self._inner_cell(input, state) 
    emit_output = (next_state, output) 
    return emit_output, next_state 

不过,好像不行。有什么想法吗?

请您参考如下方法:

建议的解决方案适用于我,但 Layer.call 方法规范更通用,因此以下 Wrapper 应该对 API 更改更稳健。你这个:

class Wrapper(tf.nn.rnn_cell.RNNCell): 
  def __init__(self, inner_cell): 
     super(Wrapper, self).__init__() 
     self._inner_cell = inner_cell 
 
  @property 
  def state_size(self): 
     return self._inner_cell.state_size 
 
  @property 
  def output_size(self): 
    return (self._inner_cell.state_size, self._inner_cell.output_size) 
 
  def call(self, input, *args, **kwargs): 
    output, next_state = self._inner_cell(input, *args, **kwargs) 
    emit_output = (next_state, output) 
    return emit_output, next_state 

这是测试:

n_steps = 2 
n_inputs = 3 
n_neurons = 5 
 
X = tf.placeholder(dtype=tf.float32, shape=[None, n_steps, n_inputs]) 
basic_cell = Wrapper(tf.nn.rnn_cell.LSTMCell(num_units=n_neurons, state_is_tuple=False)) 
outputs, states = tf.nn.dynamic_rnn(basic_cell, X, dtype=tf.float32) 
print(outputs, states) 
 
X_batch = np.array([ 
  # t = 0      t = 1 
  [[0, 1, 2], [9, 8, 7]], # instance 0 
  [[3, 4, 5], [0, 0, 0]], # instance 1 
  [[6, 7, 8], [6, 5, 4]], # instance 2 
  [[9, 0, 1], [3, 2, 1]], # instance 3 
]) 
 
with tf.Session() as sess: 
  sess.run(tf.global_variables_initializer()) 
  outputs_val = outputs[0].eval(feed_dict={X: X_batch}) 
  print(outputs_val) 

返回的outputs是(?, 2, 10)和(?, 2, 5)张量的元组,都是LSTM 状态和输出。请注意,我使用的是 LSTMCell 的“毕业”版本,来自 tf.nn.rnn_cell 包,而不是 tf.contrib.rnn。另请注意 state_is_tuple=True 以避免处理 LSTMStateTuple。