我尝试使用同一问题中接受的解决方案中描述的方法对给定 here 的数据进行排序。我制作了列表列表,而不是集合列表,并尝试使用 sorted
方法进行两次排序。但它没有用。我想要与上面链接中给出的相同的输出。这是我的输出:
[['k3', '9.2603346875', '0.4639390435'],
['K1', '4.1458078125', '0.5129700421'],
['k2', '9.5360690625', '0.5481493305'],
['k7', '9.8022878125', '0.562983695'],
['k2', '6.319044375', '0.6469451082'],
['k5', '7.2702040625', '0.6632701035'],
['K1', '8.6394253125', '0.6690271589'],
['K1', '8.025495625', '0.7561548244'],
['k8', '5.44912125', '0.8532092538'],
['k6', '7.73398625', '1.017231759'],
['K1', '6.66228125', '1.0444456163'],
['k4', '10.6868384375', '1.1287761798'],
['k9', '7.5859665625', '1.276779643'],
['K1', '6.48153375', '1.4176140292']]
这是我的代码:
path = "C:\\Chandresh_WORK\\data\\"
inpfile = 'demo1.txt'
mylist=[]
from operator import itemgetter
with open(path+inpfile,'r') as fid:
for line in fid:
myset = list(line.split())
mylist.append(myset)
mylist
s=sorted(mylist,key=itemgetter(0))
sorted(s,key=itemgetter(2))
请您参考如下方法:
您需要将字符串转换为数字类型以避免字典排序,然后反转第二个排序标准的顺序以使其降序:
s = sorted(mylist,key=lambda x: (x[0], -float(x[2])))
# ^ invert sort order
[['K1', '6.48153375', '1.4176140292'],
['K1', '6.66228125', '1.0444456163'],
['K1', '8.025495625', '0.7561548244'],
['K1', '8.6394253125', '0.6690271589'],
['K1', '4.1458078125', '0.5129700421'],
['k2', '6.319044375', '0.6469451082'],
['k2', '9.5360690625', '0.5481493305'],
['k3', '9.2603346875', '0.4639390435'],
['k4', '10.6868384375', '1.1287761798'],
['k5', '7.2702040625', '0.6632701035'],
['k6', '7.73398625', '1.017231759'],
['k7', '9.8022878125', '0.562983695'],
['k8', '5.44912125', '0.8532092538'],
['k9', '7.5859665625', '1.276779643']]