我想使用 ListView 按学校和州生成学位列表。例如,我想使用 Program 模型中的 degree_awarded 字段来列出“宾夕法尼亚州可以获得学士学位的学校”。
模型
class State(models.Model):
state_name = models.CharField(max_length=20, default='')
state_slug = models.SlugField()
def __str__(self):
return self.state_slug
class City(models.Model):
city_name = models.CharField(max_length=55, default='')
city_slug = models.SlugField()
state = models.ForeignKey(State, null=True)
def __str__(self):
return self.city_slug
class School(models.Model):
school_name = models.CharField(max_length=55, default='')
school_slug = models.SlugField()
city = models.ForeignKey(City, null=True)
def __str__(self):
return self.school_slug
def sorted_programs(self):
return self.program_set.all().order_by('program_name')
class Program(models.Model):
program_name = models.CharField(max_length=100, default='')
program_slug = models.SlugField(max_length=100, default='')
school = models.ForeignKey(School, null=True)
degree_awarded = models.CharField(max_length=10, default='')
def __str__(self):
return self.program_slug
浏览量
class SchoolIndexView(ListView):
model = State
def get_context_data(self, **kwargs):
context = super(SchoolIndexView, self).get_context_data(**kwargs)
context['state_list'] = State.objects.all().order_by('state_name')
return context
class ProgramInSchoolView(DetailView):
model = School
template = 'school_detail.html'
def get_object(self):
school_slug = School.objects.get(
school_slug=self.kwargs.get('school_slug')
)
return school_slug
def get_context_data(self, **kwargs):
context = super(ProgramInSchoolView, self).get_context_data(**kwargs)
context['school'] = self.object
context['program_list'] = self.object.program_set.all().order_by('program_name')
return context
class ProgramView(DetailView):
model = Program
template = 'program_detail.html'
def get_object(self):
program_slug = Program.objects.get(
program_slug=self.kwargs.get('program_slug')
)
return program_slug
def get_context_data(self, **kwargs):
context = super(ProgramView, self).get_context_data(**kwargs)
context['program'] = self.object
context['program_classes'] = self.object.classes_set.all().order_by('class_number')
return context
class DegreeView(ListView):
model = Program
template = 'degree_list.html'
def get_context_data(self, **kwargs):
context = super(DegreeView, self).get_context_data(**kwargs)
context['state_for_degree'] = State.objects.get(state_slug=self.kwargs.get('state_slug'))
context['city_for_degree'] = City.objects.get(city_name=self.kwargs.get('city_name'))
context['school_for_degree'] = School.objects.get(school_slug=self.kwargs.get('school_slug'))
context['degree_by_state'] = Program.objects.get(degree_awarded=self.kwargs.get('degree_awarded')).filter(school_slug=school_slug).filter(city_slug=city_slug).filter(state_slug=state_slug).order_by('city_name')
return context
网址
url(r'^(?P<state_slug>[\w-]+)/$', CityInStateView.as_view(), name='state_detail'),
url(r'^(?P<state_slug>[\w-]+)/(?P<school_slug>[\w-]+)/$', ProgramInSchoolView.as_view(), name='school_detail'),
url(r'^(?P<state_slug>[\w-]+)/(?P<school_slug>[\w-]+)/(?P<program_slug>[\w-]+)/$', ProgramView.as_view(), name='program_detail'),
url(r'^(?P<state_slug<[\w-]+)/(?P<program_slug>[\w-]+)/$', DegreeView.as_view(), name='degree_list'),
我无法弄清楚如何编写 View 和 url 路由,以便我可以使用我在 Program 模型的 degree_awarded 字段中已有的信息来生成列表。
有人能给我指出正确的方向吗?
谢谢。
编辑:我添加了之前遗漏的相关模型。我想简明扼要。我还在我试过的最后一个过滤器中添加了。它仍然没有生成按州排序的学位列表。
请您参考如下方法:
我认为您不需要 get_context_data 方法中的所有代码。您应该自定义要在 get_queryset 中显示的对象列表方法。
class DegreeView(ListView):
model = Program
template = 'degree_list.html'
def get_queryset(self):
queryset = super(DegreeView, self).get_queryset()
# batchelors degrees only
queryset = queryset.filter(program_slug=self.kwargs['program_slug'])
# filter by state
queryset = queryset.filter(school__city__state__slug=self.kwargs['state_slug'])
return queryset
请参阅 lookups that span multiple relationships 上的文档解释 school__city__state__slug 过滤器。
然后在您的模板中,您可以循环遍历程序,例如:
{% for program in object_list %}
{{ program.degree_awarded %}
