假设我有几个 <a>字符串中的元素:
s = 'Hello world. <a href="https://stackoverflow.com/">StackOverflow</a> is a great website. <a href="https://www.espn.com/">ESPN</a> is another great website.'
目标是拆分字符串，以便我得到类似于下面的列表:
l = [
"Hello world. ",
{"link": "https://stackoverflow.com/", "title": "StackOverflow"},
" is a great website. ",
{"link": "https://www.espn.com/", "title": "ESPN"},
" is another great website.",
]
字典可以是我可以从中提取链接和标题的任何对象。有没有我可以用来完成这个的正则表达式？或者有更好的方法吗？
请您参考如下方法:
BeautifulSoup 是比正则表达式更好的工具来解析这个字符串。作为一般规则，不要使用正则表达式来解析 HTML:
s = 'Hello world. <a href="https://stackoverflow.com/">StackOverflow</a> is a great website. <a href="https://www.espn.com/">ESPN</a> is another great website.'
from bs4 import BeautifulSoup, Tag, NavigableString
soup = BeautifulSoup(s, 'html.parser')
out = []
for c in soup.contents:
if isinstance(c, NavigableString):
out += [c]
elif isinstance(c, Tag) and c.name == 'a' and 'href' in c.attrs:
out += [{"link": c['href'], "title": c.text}]
from pprint import pprint
pprint(out)
打印:
['Hello world. ',
{'link': 'https://stackoverflow.com/', 'title': 'StackOverflow'},
' is a great website. ',
{'link': 'https://www.espn.com/', 'title': 'ESPN'},
' is another great website.']
