我在 python 中使用 any()
from inActivePhrase import phrase
detailslist=[]
for detail in detailslist:
inactive = any(term in detail for term in phrase)
短语将包含如下所示的字符串列表
phrase = ["not active","Closed",etc..]
该功能运行良好。但我想得到细节中存在的短语。
示例:
detail = "this is not active"
inactive = any(term in detail for term in phrase)
if inactive:
print('matched phrase' + term) //how can i do this
其中“not active”是匹配的短语。所以我想打印它。
我该怎么做。谁能帮我 ？
谢谢，
请您参考如下方法:
你可以有多个术语匹配细节
detail = "this is not active"
inactive = [term for term in phrase if term in detail]
if inactive:
print('matched phrases' + inactive)
