Python从给定字符串中过滤数据

我有以下数据:

data = """ 
item: apple 
store name: USA_1 
store id: 1000 
total: 200 
 
item: apple 
store name: USA_2 
store id: 1001 
total: 230 
 
item: apple 
store name: USA_3 
store id: 1002 
total: 330 
 
item: apple 
store name: UK1 
store id: 2000 
total: 20 
 
item: apple 
store name: UK_2 
store id: 1021 
total: 230 
""" 

我必须得到像下面这样的存储字典格式:

{' USA_1': ' 1000', ' USA_2': ' 1001', ' USA_3': ' 1002', ' UK1': ' 2000', ' UK_2': ' 1021'} 

我写了下面的代码，将获得上面的输出:

STORE_NAME_GATHERED = [] 
STORE_IDS_GATHERED = [] 
STORE_info = {} 
for line in data.split("\n"): 
    line = line.strip() 
    if line.startswith("store name:"): 
        name = line.split(":")[1] 
        if not name in  STORE_NAME_GATHERED: 
            STORE_NAME_GATHERED.append(name) 
    elif line.startswith("store id:"): 
        id = line.split(":")[1] 
        if not id in STORE_IDS_GATHERED: 
            STORE_IDS_GATHERED.append(id) 
            STORE_info[name] = id 
print(STORE_info) 

我从上面的代码中得到了预期的结果，但是它不是实现上述输出的最佳代码并且不可靠，有人可以用正确的代码帮助我以可靠的方式实现相同的结果吗

请您参考如下方法:

使用正则表达式

例如:

import re 
 
 
data = """ 
item: apple 
store name: USA_1 
store id: 1000 
total: 200 
 
item: apple 
store name: USA_2 
store id: 1001 
total: 230 
 
item: apple 
store name: USA_3 
store id: 1002 
total: 330 
 
item: apple 
store name: UK1 
store id: 2000 
total: 20 
 
item: apple 
store name: UK_2 
store id: 1021 
total: 230 
""" 
 
name = re.findall(r"store name: (.*)", data)   #Get Store Name 
store = re.findall(r"store id: (.*)", data)    #Get Store ID 
 
print(dict(zip(name, store))) 

输出:

{'UK1': '2000', 
 'UK_2': '1021', 
 'USA_1': '1000', 
 'USA_2': '1001', 
 'USA_3': '1002'}