我有一个字符串，其中包含代表多边形的坐标列表。 在这个列表中，每个多边形都有相同的起始和结束坐标。 我需要将每个多边形放在单独的字符串(或列表)中。
'17.17165756225586 -28.102264404296875,17.184370040893555 -28.200496673583984,17.1986083984375 -28.22361373901365728165 -28.2236137390136517.81655 -2655 28.102264404296875, 28.865726470947266 -28.761619567871094,28.80694007873535 -28.75750160217285,28.792499542236328 -28.706947326660156,2827.8765 61619567871094
所以从这个简单的例子我需要有两个元素:
One = '17.17165756225586 -28.102264404296875,17.184370040893555 -28.200496673583984,17.1986083984375 -28.223613739013677.816515 -28.223613739013677.816515 -26515 28.102264404296875'
两个='28.865726470947266 -28.761619567871094,28.80694007873535 -28.75750160217285,28.792499542236328 -28.706947326660502236328 -28.7069473266601564,7 66 -28.761619567871094'*
字符串中可以有更多的多边形，每个多边形都需要分开。 为此，我只能使用标准的 Python 库
请您参考如下方法:
s='17.17165756225586 -28.102264404296875,17.184370040893555 -28.200496673583984,17.1986083984375 -28.223613739013672,17.17165756225586 -28.102264404296875, 28.865726470947266 -28.761619567871094,28.80694007873535 -28.75750160217285,28.792499542236328 -28.706947326660156, 28.865726470947266 -28.761619567871094'
#convert the input in a list of points
coordinates = [tuple(map(float,el.split())) for el in s.split(",")]
polygons = []
#find the polygons
while coordinates:
ind = coordinates[1:].index(coordinates[0])
polygons.append(coordinates[0:ind+2])
coordinates = coordinates[ind+2:]
#output
[(17.17165756225586, -28.102264404296875), (17.184370040893555, -28.200496673583984), (17.1986083984375, -28.223613739013672), (17.17165756225586, -28.102264404296875)]
[(28.865726470947266, -28.761619567871094), (28.80694007873535, -28.75750160217285), (28.792499542236328, -28.706947326660156), (28.865726470947266, -28.761619567871094)]
